If it's not what You are looking for type in the equation solver your own equation and let us solve it.
20n^2+92n+48=0
a = 20; b = 92; c = +48;
Δ = b2-4ac
Δ = 922-4·20·48
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-68}{2*20}=\frac{-160}{40} =-4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+68}{2*20}=\frac{-24}{40} =-3/5 $
| -3x+15=-5x+3 | | 3k^2-4k-4=0 | | x-20x/100=500 | | x-20x/100=2000 | | x-20x/100=1500 | | -5+4m=19 | | 2a-9=29 | | 4x-x+4x=40 | | ×+2y=-1 | | 100=1/10x | | w^2=43 | | 4-12x=5x+2 | | -7r+5r+37=2r-25 | | 4=0,25x | | 4(8x+6)=9(3x+6) | | 3×+10y=15 | | 0.7-15+n=2n-80.4n | | 0.42=0.03s=3.33-s | | 3x-2(x+1)=5(x+2 | | 4x-7=5²+2³ | | -8f-16f^2=0 | | 2(3x+5)-7=3(5x-2) | | -8/3f(7-5f)=0 | | 15x(x+2)=6x(2x+7) | | 9-2y=4²-19 | | 5m+4=20-3m | | 3x4+12=60 | | 3-(2x-4)=3 | | 3-(2x-4)=4 | | -2x+47=2x+11 | | 5x+20=2x-5 | | 5p÷2=15 |